📐 사용성 설계, 기준 6종 비교 (조항, 식, 원문, 계산)

$$\begin{aligned}f_r &= 0.63\sqrt{30} = 3.45\ \text{MPa} \\ I_g &= \tfrac{400\times600^3}{12} = 7{,}200\times10^6\ \text{mm}^4 \\ M_{cr} &= \frac{f_r I_g}{y_t} = \frac{3.45\times7{,}200\times10^6}{300} = \boxed{\mathbf{82.8}\ \text{kN}\cdot\text{m}} \\ M_s &= 120\ >\ M_{cr} = 82.8\ \to\ \text{균열 단면 → 균열 및 처짐 검토}\end{aligned}$$

$$\begin{aligned}f_r &= 0.63\sqrt{30} = 3.45\ \text{MPa} \\ I_g &= \tfrac{400\times600^3}{12} = 7{,}200\times10^6\ \text{mm}^4 \\ M_{cr} &= \frac{f_r I_g}{y_t} = \frac{3.45\times7{,}200\times10^6}{300} = \boxed{\mathbf{82.8}\ \text{kN}\cdot\text{m}} \\ M_s &= 120\ >\ 0.8M_{cr} = 66.3\ \to\ \text{균열 단면 → 균열 및 처짐 검토}\end{aligned}$$

$$\begin{aligned}f_r &= 0.63\sqrt{30} = 3.45\ \text{MPa} \\ I_g &= \tfrac{400\times600^3}{12} = 7{,}200\times10^6\ \text{mm}^4 \\ M_{cr} &= \frac{f_r I_g}{y_t} = \frac{3.45\times7{,}200\times10^6}{300} = \boxed{\mathbf{82.8}\ \text{kN}\cdot\text{m}} \\ M_s &= 120\ >\ M_{cr} = 82.8\ \to\ \text{균열 단면 → 균열 및 처짐 검토}\end{aligned}$$

$$\begin{aligned}f_r &= 0.62\sqrt{30} = 3.40\ \text{MPa} \\ I_g &= \tfrac{400\times600^3}{12} = 7{,}200\times10^6\ \text{mm}^4 \\ M_{cr} &= \frac{f_r I_g}{y_t} = \frac{3.40\times7{,}200\times10^6}{300} = \boxed{\mathbf{81.5}\ \text{kN}\cdot\text{m}} \\ M_s &= 120\ >\ M_{cr} = 81.5\ \to\ \text{균열 단면 → 균열 및 처짐 검토}\end{aligned}$$

$$\begin{aligned}f_r &= 0.62\sqrt{30} = 3.40\ \text{MPa} \\ I_g &= \tfrac{400\times600^3}{12} = 7{,}200\times10^6\ \text{mm}^4 \\ M_{cr} &= \frac{f_r I_g}{y_t} = \frac{3.40\times7{,}200\times10^6}{300} = \boxed{\mathbf{81.5}\ \text{kN}\cdot\text{m}} \\ M_s &= 120\ >\ 0.8M_{cr} = 65.2\ \to\ \text{균열 단면 → 균열 및 처짐 검토}\end{aligned}$$

$$\begin{aligned}f_r &= 0.63\sqrt{30} = 3.45\ \text{MPa} \\ I_g &= \tfrac{400\times600^3}{12} = 7{,}200\times10^6\ \text{mm}^4 \\ M_{cr} &= \frac{f_r I_g}{y_t} = \frac{3.45\times7{,}200\times10^6}{300} = \boxed{\mathbf{82.8}\ \text{kN}\cdot\text{m}} \\ M_s &= 120\ >\ M_{cr} = 82.8\ \to\ \text{균열 단면 → 균열 및 처짐 검토}\end{aligned}$$

$$\begin{aligned}E_c &= 27.5\ \text{GPa} \\ n &= E/E_c = 200{,}000/27{,}537 = 7.26 \\ \rho &= \frac{A}{bd} = \frac{3{,}040}{400\times509} = 0.0149 \\ k &= \sqrt{2\rho n+(\rho n)^2}-\rho n = 0.370 \\ I_{cr} &= \tfrac{bd^3}{3}k^3 + nAd^2(1-k)^2 = 3{,}161\times10^6\ \text{mm}^4 \\ f_{s} &= \frac{M_s\,n\,d(1-k)}{I_{cr}} = \frac{120\times10^6\times7.26\times509\times(1-0.370)}{3{,}161\times10^6} = \boxed{\mathbf{88}\ \text{MPa}}\end{aligned}$$

$$\begin{aligned}E_c &= 27.5\ \text{GPa} \\ n &= E/E_c = 45{,}000/27{,}537 = 1.63 \\ \rho &= \frac{A}{bd} = \frac{3{,}040}{400\times509} = 0.0149 \\ k &= \sqrt{2\rho n+(\rho n)^2}-\rho n = 0.198 \\ I_{cr} &= \tfrac{bd^3}{3}k^3 + nAd^2(1-k)^2 = 964\times10^6\ \text{mm}^4 \\ f_{fs} &= \frac{M_s\,n\,d(1-k)}{I_{cr}} = \frac{120\times10^6\times1.63\times509\times(1-0.198)}{964\times10^6} = \boxed{\mathbf{83}\ \text{MPa}}\end{aligned}$$

$$\begin{aligned}E_c &= 27.5\ \text{GPa} \\ n &= E/E_c = 45{,}000/27{,}537 = 1.63 \\ \rho &= \frac{A}{bd} = \frac{3{,}040}{400\times509} = 0.0149 \\ k &= \sqrt{2\rho n+(\rho n)^2}-\rho n = 0.198 \\ I_{cr} &= \tfrac{bd^3}{3}k^3 + nAd^2(1-k)^2 = 964\times10^6\ \text{mm}^4 \\ f_{fs} &= \frac{M_s\,n\,d(1-k)}{I_{cr}} = \frac{120\times10^6\times1.63\times509\times(1-0.198)}{964\times10^6} = \boxed{\mathbf{83}\ \text{MPa}}\end{aligned}$$

$$\begin{aligned}E_c &= 25.7\ \text{GPa} \\ n &= E/E_c = 45{,}000/25{,}743 = 1.75 \\ \rho &= \frac{A}{bd} = \frac{3{,}040}{400\times509} = 0.0149 \\ k &= \sqrt{2\rho n+(\rho n)^2}-\rho n = 0.204 \\ I_{cr} &= \tfrac{bd^3}{3}k^3 + nAd^2(1-k)^2 = 1{,}022\times10^6\ \text{mm}^4 \\ f_{fs} &= \frac{M_s\,n\,d(1-k)}{I_{cr}} = \frac{120\times10^6\times1.75\times509\times(1-0.204)}{1{,}022\times10^6} = \boxed{\mathbf{83}\ \text{MPa}}\end{aligned}$$

$$\begin{aligned}E_c &= 25.7\ \text{GPa} \\ n &= E/E_c = 45{,}000/25{,}743 = 1.75 \\ \rho &= \frac{A}{bd} = \frac{3{,}040}{400\times509} = 0.0149 \\ k &= \sqrt{2\rho n+(\rho n)^2}-\rho n = 0.204 \\ I_{cr} &= \tfrac{bd^3}{3}k^3 + nAd^2(1-k)^2 = 1{,}022\times10^6\ \text{mm}^4 \\ f_{fs} &= \frac{M_s\,n\,d(1-k)}{I_{cr}} = \frac{120\times10^6\times1.75\times509\times(1-0.204)}{1{,}022\times10^6} = \boxed{\mathbf{83}\ \text{MPa}}\end{aligned}$$

$$\begin{aligned}E_c &= 25.7\ \text{GPa} \\ n &= E/E_c = 45{,}000/25{,}743 = 1.75 \\ \rho &= \frac{A}{bd} = \frac{3{,}040}{400\times509} = 0.0149 \\ k &= \sqrt{2\rho n+(\rho n)^2}-\rho n = 0.204 \\ I_{cr} &= \tfrac{bd^3}{3}k^3 + nAd^2(1-k)^2 = 1{,}022\times10^6\ \text{mm}^4 \\ f_{fs} &= \frac{M_s\,n\,d(1-k)}{I_{cr}} = \frac{120\times10^6\times1.75\times509\times(1-0.204)}{1{,}022\times10^6} = \boxed{\mathbf{83}\ \text{MPa}}\end{aligned}$$

$$\begin{aligned}s_1 &= 375\frac{\kappa_{cr}}{f_s}-2.5c_c = 375\times\frac{280}{88}-2.5\times53 = 1{,}055 \\ s_2 &= 300\frac{\kappa_{cr}}{f_s} = 300\times\frac{280}{88} = 950 \\ s_{max} &= \min(s_1,\,s_2) = \boxed{\mathbf{950}\ \text{mm}} \\ s &= \frac{b-2c_c-d_b}{n-1} = \frac{400-2\times53-25.4}{3-1} = 134\ \le\ s_{max}\ \ \color{#0a8a2a}{\checkmark\ \textbf{OK}}\end{aligned}$$

$$\begin{aligned}\frac{E_fw}{f_{fs}k_b} &= \frac{45{,}000\times0.7}{83\times1.20} = 316.2 \\ s_1 &= 1.15\times316.2-2.5\times53 = 231 \\ s_2 &= 0.94\times316.2 = 297 \\ s_{max} &= \min(s_1,\,s_2) = \boxed{\mathbf{231}\ \text{mm}} \\ s &= \frac{b-2c_c-d_b}{n-1} = \frac{400-2\times53-25.4}{3-1} = 134\ \le\ s_{max}\ \ \color{#0a8a2a}{\checkmark\ \textbf{OK}}\end{aligned}$$

$$\begin{aligned}\frac{C_b\,E_f w}{f_{fs}} &= \frac{0.83\times45{,}000\times0.7}{83} = 314.9 \\ s_1 &= 1.15\times314.9-2.5\times53 = 230 \\ s_2 &= 0.92\times314.9 = 290 \\ s_{max} &= \min(s_1,\,s_2) = \boxed{\mathbf{230}\ \text{mm}} \\ s &= \frac{b-2c_c-d_b}{n-1} = \frac{400-2\times53-25.4}{3-1} = 134\ \le\ s_{max}\ \ \color{#0a8a2a}{\checkmark\ \textbf{OK}}\end{aligned}$$

$$\begin{aligned}\frac{E_fw}{f_{fs}k_b} &= \frac{45{,}000\times0.7}{83\times1.40} = 270.4 \\ s_1 &= 1.15\times270.4-2.5\times53 = 178 \\ s_2 &= 0.92\times270.4 = 249 \\ s_{max} &= \min(s_1,\,s_2) = \boxed{\mathbf{178}\ \text{mm}} \\ s &= \frac{b-2c_c-d_b}{n-1} = \frac{400-2\times53-25.4}{3-1} = 134\ \le\ s_{max}\ \ \color{#0a8a2a}{\checkmark\ \textbf{OK}}\end{aligned}$$

$$\begin{aligned}\frac{E_fw}{f_{fs}k_b} &= \frac{45{,}000\times0.7}{83\times1.20} = 315.5 \\ s_1 &= 1.15\times315.5-2.5\times53 = 230 \\ s_2 &= 0.92\times315.5 = 290 \\ s_{max} &= \min(s_1,\,s_2) = \boxed{\mathbf{230}\ \text{mm}} \\ s &= \frac{b-2c_c-d_b}{n-1} = \frac{400-2\times53-25.4}{3-1} = 134\ \le\ s_{max}\ \ \color{#0a8a2a}{\checkmark\ \textbf{OK}}\end{aligned}$$

$$\begin{aligned}\frac{C_b\,E_f w}{f_{fs}} &= \frac{0.83\times45{,}000\times0.7}{83} = 314.2 \\ s_1 &= 1.15\times314.2-2.5\times53 = 229 \\ s_2 &= 0.92\times314.2 = 289 \\ s_{max} &= \min(s_1,\,s_2) = \boxed{\mathbf{229}\ \text{mm}} \\ s &= \frac{b-2c_c-d_b}{n-1} = \frac{400-2\times53-25.4}{3-1} = 134\ \le\ s_{max}\ \ \color{#0a8a2a}{\checkmark\ \textbf{OK}}\end{aligned}$$

$$\begin{aligned}\beta_{cr} &= \frac{h-kd}{d-kd} = \frac{600-100.7}{509-100.7} = 1.223 \\ d_c &= c_c+d_b/2 = 65.7\ \text{mm} \\ f_{fs,lim} &= \frac{0.36E_f}{d_c\beta_{cr}k_b} = \frac{0.36\times45{,}000}{65.7\times1.223\times1.20} = \boxed{\mathbf{168}\ \text{MPa}} \\ f_{fs} &= 83\ \le\ 168\ \ \color{#0a8a2a}{\checkmark\ \textbf{OK}}\end{aligned}$$

$$\begin{aligned}\beta_{cr} &= \frac{h-kd}{d-kd} = \frac{600-100.7}{509-100.7} = 1.223 \\ d_c &= c_c+d_b/2 = 65.7\ \text{mm} \\ d_{c,lim} &= \frac{C_b\,E_f w}{2f_{fs}\beta} = \frac{0.83\times45{,}000\times0.7}{2\times83\times1.223} = \boxed{\mathbf{128.8}\ \text{mm}} \\ d_c &= 65.7\ \le\ 128.8\ \ \color{#0a8a2a}{\checkmark\ \textbf{OK}}\end{aligned}$$

$$\begin{aligned}\beta_{cr} &= \frac{h-kd}{d-kd} = \frac{600-103.8}{509-103.8} = 1.225 \\ d_c &= c_c+d_b/2 = 65.7\ \text{mm} \\ d_{c,lim} &= \frac{E_fw}{2f_{fs}\beta k_b} = \frac{45{,}000\times0.7}{2\times83\times1.225\times1.40} = \boxed{\mathbf{110.4}\ \text{mm}} \\ d_c &= 65.7\ \le\ 110.4\ \ \color{#0a8a2a}{\checkmark\ \textbf{OK}}\end{aligned}$$

$$\begin{aligned}\beta_{cr} &= \frac{h-kd}{d-kd} = \frac{600-103.8}{509-103.8} = 1.225 \\ d_c &= c_c+d_b/2 = 65.7\ \text{mm} \\ f_{fs,lim} &= \frac{0.36E_f}{d_c\beta_{cr}k_b} = \frac{0.36\times45{,}000}{65.7\times1.225\times1.20} = \boxed{\mathbf{168}\ \text{MPa}} \\ f_{fs} &= 83\ \le\ 168\ \ \color{#0a8a2a}{\checkmark\ \textbf{OK}}\end{aligned}$$

$$\begin{aligned}\beta_{cr} &= \frac{h-kd}{d-kd} = \frac{600-103.8}{509-103.8} = 1.225 \\ d_c &= c_c+d_b/2 = 65.7\ \text{mm} \\ d_{c,lim} &= \frac{C_b\,E_f w}{2f_{fs}\beta} = \frac{0.83\times45{,}000\times0.7}{2\times83\times1.225} = \boxed{\mathbf{128.3}\ \text{mm}} \\ d_c &= 65.7\ \le\ 128.3\ \ \color{#0a8a2a}{\checkmark\ \textbf{OK}}\end{aligned}$$

$$\begin{aligned}\kappa_{cr} &= 280\ (\text{건조환경})\end{aligned}$$

$$\begin{aligned}k_b &= 1.20 \\ w &= 0.7\ \text{mm}\end{aligned}$$

$$\begin{aligned}C_b &= 0.83\ (k_b = 1/C_b = 1.20) \\ w &= 0.7\ \text{mm}\end{aligned}$$

$$\begin{aligned}k_b &= 1.40 \\ w &= 0.7\ \text{mm}\end{aligned}$$

$$\begin{aligned}k_b &= 1.20 \\ w &= 0.7\ \text{mm}\end{aligned}$$

$$\begin{aligned}C_b &= 0.83\ (k_b = 1/C_b = 1.20) \\ w &= 0.7\ \text{mm}\end{aligned}$$

$$\begin{aligned}\left(\tfrac{M_{cr}}{M_a}\right)^3 &= \left(\tfrac{82.8}{120}\right)^3 = 0.3287 \\ I_e &= 0.3287\times7{,}200 + (1-0.3287)\times3{,}161 = \boxed{\mathbf{4{,}489}\ \text{×10⁶ mm⁴}} \\ \frac{I_e}{I_g} &= \mathbf{0.623}\end{aligned}$$

$$\begin{aligned}\gamma &= 1.72-0.72\left(\tfrac{0.8M_{cr}}{M_a}\right) = 1.72-0.72\times0.552 = 1.322 \\ I_e &= \frac{I_{cr}}{1-\gamma\left(\tfrac{0.8M_{cr}}{M_a}\right)^2\left[1-\tfrac{I_{cr}}{I_g}\right]} = \frac{964}{1-1.322\times0.552^2\times(1-0.134)} \\ &= \boxed{\mathbf{1{,}482}\ \text{×10⁶ mm⁴}} \\ \frac{I_e}{I_g} &= \mathbf{0.206}\end{aligned}$$

$$\begin{aligned}\gamma &= 1.72-0.72\left(\tfrac{M_{cr}}{M_a}\right) = 1.72-0.72\times0.690 = 1.223 \\ I_e &= \frac{I_{cr}}{1-\gamma\left(\tfrac{M_{cr}}{M_a}\right)^2\left[1-\tfrac{I_{cr}}{I_g}\right]} = \frac{964}{1-1.223\times0.690^2\times(1-0.134)} \\ &= \boxed{\mathbf{1{,}946}\ \text{×10⁶ mm⁴}} \\ \frac{I_e}{I_g} &= \mathbf{0.270}\end{aligned}$$

$$\begin{aligned}\gamma &= 1.72-0.72\left(\tfrac{M_{cr}}{M_a}\right) = 1.72-0.72\times0.679 = 1.231 \\ I_e &= \frac{I_{cr}}{1-\gamma\left(\tfrac{M_{cr}}{M_a}\right)^2\left[1-\tfrac{I_{cr}}{I_g}\right]} = \frac{1{,}022}{1-1.231\times0.679^2\times(1-0.142)} \\ &= \boxed{\mathbf{1{,}992}\ \text{×10⁶ mm⁴}} \\ \frac{I_e}{I_g} &= \mathbf{0.277}\end{aligned}$$

$$\begin{aligned}\gamma &= 1.72-0.72\left(\tfrac{0.8M_{cr}}{M_a}\right) = 1.72-0.72\times0.543 = 1.329 \\ I_e &= \frac{I_{cr}}{1-\gamma\left(\tfrac{0.8M_{cr}}{M_a}\right)^2\left[1-\tfrac{I_{cr}}{I_g}\right]} = \frac{1{,}022}{1-1.329\times0.543^2\times(1-0.142)} \\ &= \boxed{\mathbf{1{,}540}\ \text{×10⁶ mm⁴}} \\ \frac{I_e}{I_g} &= \mathbf{0.214}\end{aligned}$$

$$\begin{aligned}\gamma &= 1.72-0.72\left(\tfrac{M_{cr}}{M_a}\right) = 1.72-0.72\times0.690 = 1.223 \\ I_e &= \frac{I_{cr}}{1-\gamma\left(\tfrac{M_{cr}}{M_a}\right)^2\left[1-\tfrac{I_{cr}}{I_g}\right]} = \frac{1{,}022}{1-1.223\times0.690^2\times(1-0.142)} \\ &= \boxed{\mathbf{2{,}043}\ \text{×10⁶ mm⁴}} \\ \frac{I_e}{I_g} &= \mathbf{0.284}\end{aligned}$$

$$\begin{aligned}\Delta_i &= K\frac{M_a L^2}{E_c I_e} = 0.1042\times\frac{120\times10^6\times6^2}{27{,}537\times4{,}489\times10^6} = 3.64\ \text{mm} \\ \Delta_{sus} &= 0.60\times3.64 = 2.18 \\ \Delta_L &= \Delta_i-\Delta_{sus} = \boxed{\mathbf{1.46}\ \text{mm}} \\ \Delta_L &\ \le\ L/360 = 16.7\ \ \color{#0a8a2a}{\checkmark\ \textbf{OK}}\end{aligned}$$

$$\begin{aligned}\Delta_i &= K\frac{M_a L^2}{E_c I_e} = 0.1042\times\frac{120\times10^6\times6^2}{27{,}537\times1{,}482\times10^6} = 11.03\ \text{mm} \\ \Delta_{sus} &= 0.60\times11.03 = 6.62 \\ \Delta_L &= \Delta_i-\Delta_{sus} = \boxed{\mathbf{4.41}\ \text{mm}} \\ \Delta_L &\ \le\ L/360 = 16.7\ \ \color{#0a8a2a}{\checkmark\ \textbf{OK}}\end{aligned}$$

$$\begin{aligned}\Delta_i &= K\frac{M_a L^2}{E_c I_e} = 0.1042\times\frac{120\times10^6\times6^2}{27{,}537\times1{,}946\times10^6} = 8.40\ \text{mm} \\ \Delta_{sus} &= 0.60\times8.40 = 5.04 \\ \Delta_L &= \Delta_i-\Delta_{sus} = \boxed{\mathbf{3.36}\ \text{mm}} \\ \Delta_L &\ \le\ L/360 = 16.7\ \ \color{#0a8a2a}{\checkmark\ \textbf{OK}}\end{aligned}$$

$$\begin{aligned}\Delta_i &= K\frac{M_a L^2}{E_c I_e} = 0.1042\times\frac{120\times10^6\times6^2}{25{,}743\times1{,}992\times10^6} = 8.77\ \text{mm} \\ \Delta_{sus} &= 0.60\times8.77 = 5.26 \\ \Delta_L &= \Delta_i-\Delta_{sus} = \boxed{\mathbf{3.51}\ \text{mm}} \\ \Delta_L &\ \le\ L/360 = 16.7\ \ \color{#0a8a2a}{\checkmark\ \textbf{OK}}\end{aligned}$$

$$\begin{aligned}\Delta_i &= K\frac{M_a L^2}{E_c I_e} = 0.1042\times\frac{120\times10^6\times6^2}{25{,}743\times1{,}540\times10^6} = 11.35\ \text{mm} \\ \Delta_{sus} &= 0.60\times11.35 = 6.81 \\ \Delta_L &= \Delta_i-\Delta_{sus} = \boxed{\mathbf{4.54}\ \text{mm}} \\ \Delta_L &\ \le\ L/360 = 16.7\ \ \color{#0a8a2a}{\checkmark\ \textbf{OK}}\end{aligned}$$

$$\begin{aligned}\Delta_i &= K\frac{M_a L^2}{E_c I_e} = 0.1042\times\frac{120\times10^6\times6^2}{25{,}743\times2{,}043\times10^6} = 8.56\ \text{mm} \\ \Delta_{sus} &= 0.60\times8.56 = 5.13 \\ \Delta_L &= \Delta_i-\Delta_{sus} = \boxed{\mathbf{3.42}\ \text{mm}} \\ \Delta_L &\ \le\ L/360 = 16.7\ \ \color{#0a8a2a}{\checkmark\ \textbf{OK}}\end{aligned}$$

$$\begin{aligned}\lambda_\Delta &= \frac{\xi}{1+50\rho'} = \frac{2}{1+50\times0} = 2.00 \\ \Delta_{lt} &= \lambda_\Delta\Delta_{sus} = 2.00\times2.18 = 4.37\ \text{mm} \\ \Delta_L+\Delta_{lt} &= 1.46+4.37 = \boxed{\mathbf{5.83}\ \text{mm}}\ \le\ L/240 = 25.0\ \ \color{#0a8a2a}{\checkmark\ \textbf{OK}}\end{aligned}$$

$$\begin{aligned}\lambda_\Delta &= 0.6\,\xi = 0.6\times2 = 1.20 \\ \Delta_{lt} &= \lambda_\Delta\Delta_{sus} = 1.20\times6.62 = 7.94\ \text{mm} \\ \Delta_L+\Delta_{lt} &= 4.41+7.94 = \boxed{\mathbf{12.35}\ \text{mm}}\ \le\ L/240 = 25.0\ \ \color{#0a8a2a}{\checkmark\ \textbf{OK}}\end{aligned}$$

$$\begin{aligned}\lambda_\Delta &= 0.6\,\xi = 0.6\times2 = 1.20 \\ \Delta_{lt} &= \lambda_\Delta\Delta_{sus} = 1.20\times5.04 = 6.05\ \text{mm} \\ \Delta_L+\Delta_{lt} &= 3.36+6.05 = \boxed{\mathbf{9.40}\ \text{mm}}\ \le\ L/240 = 25.0\ \ \color{#0a8a2a}{\checkmark\ \textbf{OK}}\end{aligned}$$

$$\begin{aligned}\lambda_\Delta &= 0.6\,\xi = 0.6\times2 = 1.20 \\ \Delta_{lt} &= \lambda_\Delta\Delta_{sus} = 1.20\times5.26 = 6.32\ \text{mm} \\ \Delta_L+\Delta_{lt} &= 3.51+6.32 = \boxed{\mathbf{9.83}\ \text{mm}}\ \le\ L/240 = 25.0\ \ \color{#0a8a2a}{\checkmark\ \textbf{OK}}\end{aligned}$$

$$\begin{aligned}\lambda_\Delta &= 0.6\,\xi = 0.6\times2 = 1.20 \\ \Delta_{lt} &= \lambda_\Delta\Delta_{sus} = 1.20\times6.81 = 8.17\ \text{mm} \\ \Delta_L+\Delta_{lt} &= 4.54+8.17 = \boxed{\mathbf{12.71}\ \text{mm}}\ \le\ L/240 = 25.0\ \ \color{#0a8a2a}{\checkmark\ \textbf{OK}}\end{aligned}$$

$$\begin{aligned}\text{배율} &= 3.0\ (I_e\ \text{기준})\ \to\ \lambda_\Delta = 3.0-1 = 2.0 \\ \Delta_{lt} &= \lambda_\Delta\Delta_{sus} = 2.00\times5.13 = 10.27\ \text{mm} \\ \Delta_L+\Delta_{lt} &= 3.42+10.27 = \boxed{\mathbf{13.69}\ \text{mm}}\ \le\ L/240 = 25.0\ \ \color{#0a8a2a}{\checkmark\ \textbf{OK}}\end{aligned}$$

$$\begin{aligned}M_{s,sus} &= 0.60\times120 = 72.0\ \text{kN}\cdot\text{m} \\ f_{fs,sus} &= \frac{M_{s,sus}\,n_f\,d(1-k)}{I_{cr}} = \boxed{\mathbf{50}\ \text{MPa}} \\ &\ \le\ 0.30f_{fu} = 0.30\times850 = 255\ \ \color{#0a8a2a}{\checkmark\ \textbf{OK}}\end{aligned}$$

$$\begin{aligned}M_{s,sus} &= 0.60\times120 = 72.0\ \text{kN}\cdot\text{m} \\ f_{fs,sus} &= \frac{M_{s,sus}\,n_f\,d(1-k)}{I_{cr}} = \boxed{\mathbf{50}\ \text{MPa}} \\ &\ \le\ 0.30f_{fu} = 0.30\times800 = 240\ \ \color{#0a8a2a}{\checkmark\ \textbf{OK}}\end{aligned}$$

$$\begin{aligned}M_{s,sus} &= 0.60\times120 = 72.0\ \text{kN}\cdot\text{m} \\ f_{fs,sus} &= \frac{M_{s,sus}\,n_f\,d(1-k)}{I_{cr}} = \boxed{\mathbf{50}\ \text{MPa}} \\ &\ \le\ 0.20f_{fu} = 0.20\times800 = 160\ \ \color{#0a8a2a}{\checkmark\ \textbf{OK}}\end{aligned}$$

$$\begin{aligned}M_{s,sus} &= 0.60\times120 = 72.0\ \text{kN}\cdot\text{m} \\ f_{fs,sus} &= \frac{M_{s,sus}\,n_f\,d(1-k)}{I_{cr}} = \boxed{\mathbf{50}\ \text{MPa}} \\ &\ \le\ 0.30f_{fu} = 0.30\times850 = 255\ \ \color{#0a8a2a}{\checkmark\ \textbf{OK}}\end{aligned}$$

$$\begin{aligned}M_{s,sus} &= 0.60\times120 = 72.0\ \text{kN}\cdot\text{m} \\ f_{fs,sus} &= \frac{M_{s,sus}\,n_f\,d(1-k)}{I_{cr}} = \boxed{\mathbf{50}\ \text{MPa}} \\ &\ \le\ 0.30f_{fu} = 0.30\times800 = 240\ \ \color{#0a8a2a}{\checkmark\ \textbf{OK}}\end{aligned}$$

$$\begin{aligned}h_{min} &= \frac{L}{16} = 0\ \text{mm}\ \le\ h = 600\ \to\ \text{처짐 계산 생략 가능}\end{aligned}$$

$$\begin{aligned}h_{min} &= \frac{L}{10} = 1\ \text{mm}\ \le\ h = 600\ (\text{초기 가정용})\end{aligned}$$

$$\begin{aligned}h_{min} &= \frac{L}{10} = 1\ \text{mm}\ \le\ h = 600\ (\text{초기 가정용})\end{aligned}$$

$$\begin{aligned}h_{min} &= \frac{L}{10} = 1\ \text{mm}\ \le\ h = 600\ (\text{초기 가정용})\end{aligned}$$